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Re: char *test[position]
On Fri, Jun 11, 1999 at 06:47:08PM +0200, Felix Kollmann wrote:
> unsigned int position= 0;
> char *test;
> printf ("%s", test[position]);
> But the programm prints the complete string down to [position] .
This would work for a non-pointer (char test[64] or so).
I think for pointers this would work:
printf("%c", test[position]);
Rob
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Rob Kaper | mail: cap@capsi.com + cap@capsi.net + cap@capsi.cx
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